STAM101 :: Lecture 19 :: 2Square Factorial Experiments in RBD – lay out – analysis

2Sqaure Factorial Experiments in RBD
22  factorial experiment means two factors each at two levels. Suppose the two factors are A and B and both are tried with two levels the total number of treatment combinations will be four i.e. a0b0, a0b1, a1b0 and a1b1.
The allotment of these four treatment combinations will be as allotted in RBD. That is each block is divided into four experimental units. By using the random numbers these four combinations are allotted at random for each block separately.
The analysis of variance table for two factors A with a levels and B with b levels with r replications tried in RBD will be as follows:


Sources of Variation

d.f.

SS

MS

F

Replications

r-1

RSS

RMS

 

Factor A

a-1

ASS

AMS

AMS / EMS

Factor B

b-1

BSS

BMS

BMS / EMS

AB (interaction)

(a-1)(b-1)

ABSS

ABMS

ABMS / EMS

Error

(r-1)(ab-1)

ESS

EMS

 

Total

rab-1

TSS

 

 

As in the previous designs calculate the replication totals to calculate the RSS, TSS in the usual way. To calculate ASS, BSS and ABSS, form a two way table A X B by taking the levels of A in rows and levels of B in the columns.  To get the values in this table the missing factor is replication. That is by adding over replication we can form this table.

RSS =
A X B Two way table


B                   A

b0

b1

Total

a0

a0 b0

a0 b1

A0

a1

a1 b0

a1 b1

A1

Total

B0

B1

Grand Total




ESS= TSS-RSS-ASS-BSS-ABSS
By substituting the above values in the ANOVA table corresponding to the columns sum of squares, the mean squares and F value can be calculated.

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